2[y-(3y-5)]=y-2

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Solution for 2[y-(3y-5)]=y-2 equation: 


Simplifying
2[y + -1(3y + -5)] = y + -2

Reorder the terms:
2[y + -1(-5 + 3y)] = y + -2
2[y + (-5 * -1 + 3y * -1)] = y + -2
2[y + (5 + -3y)] = y + -2

Reorder the terms:
2[5 + y + -3y] = y + -2

Combine like terms: y + -3y = -2y
2[5 + -2y] = y + -2
[5 * 2 + -2y * 2] = y + -2
[10 + -4y] = y + -2

Reorder the terms:
10 + -4y = -2 + y

Solving
10 + -4y = -2 + y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-1y' to each side of the equation.
10 + -4y + -1y = -2 + y + -1y

Combine like terms: -4y + -1y = -5y
10 + -5y = -2 + y + -1y

Combine like terms: y + -1y = 0
10 + -5y = -2 + 0
10 + -5y = -2

Add '-10' to each side of the equation.
10 + -10 + -5y = -2 + -10

Combine like terms: 10 + -10 = 0
0 + -5y = -2 + -10
-5y = -2 + -10

Combine like terms: -2 + -10 = -12
-5y = -12

Divide each side by '-5'.
y = 2.4

Simplifying
y = 2.4

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